Hexafex

How to Solve

If you get stuck trying to solve then looking here may give you some helpful hints and tips.

In this case A must contain 1 as all other numbers have been placed.	In this case A cannot be 6 or 5 since they are already around circle X. A cannot be 2 or 3 since they are already around circle Y and A cannot be 4 since it is already around circle Z. Therefore it must be 1

In this case A must be 6 because it is the only place around circle Y which would not cause 6 to be placed twice around circles X and Z. Then B must be 1 other else it would have to be placed twice around circle X.	In this case A must be 1.

In this case A must be 6. This is because it is the only place that 6 can be placed around circle X without causing 6 to be placed twice around other circles.

	Step 1. Here A must be 6 as it is the only place that place that 6 can be placed around circle X without causing 6 to be placed twice around other circles.
Step 2. Now 6 has been placed B must be 1 and C must be 3.
	Step 3. Now D must be 6 and E must be 4.
Step 4. Now 5 is the only number not to be placed around circle Y so F must be 5.
	Step 5. Now G must be 2 and H must be 5.
Step 6. Now I must be 4 and J must be 2 and this Hexafex is on its way to being solved.